B^(1/3)27

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Solution for B^(1/3)27 equation: 


B in (-oo:+oo)

B^(1/3) > 27 // - 27

B^(1/3)-27 > 0

1*B^(1/3) > 27

1*B^(1/3) > 27 // : 1

B^(1/3) > 27/1

B^(1/3) > 27

B >= 0

B^(1/3) > 27 // ^ 1/1/3

B^(1/3) > 27 // ^ 3

abs(B) > 19683

B > 19683

B in (19683:+oo)

B in (19683:+oo)

(19683:+oo)

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